Amisha makes a star with the help of line segments a, b, c, d, e and f, in which a || d, b || e and c || f. Chhaya marks an angle as 120° as shown in the given figure and Amisha to find the ∠x, ∠y and ∠z. Therefore, B will be less than 45°. Question 108: (ii) Let the angle between d and e is ∠2. (i) EF and GH Hence, two right angles are never be complementary. The above Practice worksheets for Class 7 Lines and Angles have been designed as per latest NCERT CBSE and KVS guidelines and 2021 syllabus. ∠APS + ∠PSC = 130° + 50° = 180° corresponding angles are on the _________ side of the transversal. Then (b) 50°, 20° Solution : (i) b and c Further, they are all designed with the latest academic year subject material so that any difference in the syllabus is accounted for as well. In the given figure, AB || CD, AF || ED, ∠AFC = 68°and ∠FED = 42°. = 60° Two supplementary angles always form a linear pair. The supplement of an obtuse angle is always an acute angle. In the given figure, if l || m, find the values of a and b. If an angle is 60° less than two times of its supplement, then the greater angle is Since, PQ and RS are parallel and TR is transversal. If ∠ABC = 46°, then ∠ABP is equal to Solution: So, their sum will be 90°. [∵ ∠P and ∠Q are supplementary angles] For given figure, statements p and q are given below: Two angles forming a________pair are supplementary. ∠ABD and ∠DBC; ∠ABE and ∠CBE are linear pairs. Hence, two situations are 45°, 45° and 30°, 60°. So, the sum of two right angles = 90° + 90° = 180°. (c) 64° \(\Rightarrow \quad b=\frac{120^{\circ}}{3}=40^{\circ}\) (c) 20° (∵ 45° + 45° = 90° and 60° + 30°= 90°). NCERT Class 7 Maths Unit 5 is for Lines and Angles. Solution: Question 86. ∴ ∠AOD + ∠AOC = 180° [Linear pair] Also, m || n and p is transversal. (a) 120° ∴ Other angle is 180° – x. So, if one angle is acute, then other angle will be acute and if one angle is obtuse, then the other will be obtuse. \(\Rightarrow \quad x=\frac{200^{\circ}}{2}=100^{\circ}\) The best feature of these solutions is a free download option. (d) 120° ⇒ ∠QPR = 130° – 50° = 80°, Question 11. Solution : Solution : ⇒ b = c – a Question 6. \(\Rightarrow \quad x=\frac{180^{\circ}}{4}=45^{\circ}\) Let the angle be x°. ⇒ 30° + 5y = 180° As, PQ is a straight line. Thus, a = 20°, b = 40° and c = 30°, Question 109. Question 29: (b) The angle between North and West is a right angle and angle between South and East is also a right angle. The sum of two vertically opposite angles is 166°. Measures (in degrees) of two supplementary angles are consecutive odd integers. Obtuse, Question 52. Solution : In the given figure, POR is a line. Since, AF || ED and FD is a transversal. (a) ∠1+ ∠5=180° (b) ∠2 + ∠5=180° Sum of angles of linear pair is 180°. Adding (i) and (ii), we get Since, AE || BD and CH is a transversal. (iii) d and f (iv) c and f (i) ∠x and ∠y; ∠x and ∠y + ∠z; ∠y and ∠z; ∠z and ∠x + ∠y are four pairs of adjacent angles. (b) 61° In the given figure, PQ, RS and UT are parallel lines. Question 24. (i) Linear pair (ii) PQ || UT and PT is a transversal. According to question, Solution : NCERT Exemplar Class 7 Maths Unit 5 Lines and Angles. l || m and QR is a transversal. Question 25: Two angles are making a linear pair. Angles between South and West and South and East are The player has a better chance of scoring a goal from position A than from position B. Question 89. Question 2: A line has no end points on either side. Since, AB || l and EF is a transversal. In the given figure, P, Q and R are collinear points and TQ ⊥ PR, In the given figure, two parallel lines l and m are cut by two transversals n and p. Find the values of x and y. Solution: In the given figure, lines PQ and ST intersect at 0. ∴ y + 80° = 180° [Co-interior angles] Solution : ⇒ ∠2 = 30° ———– (ii) ∴ ∠PQR – ∠QRS = 85° ———– (i) [Alternate interior angles] True Solution : 5.1; Class 7 Maths Chapter 5 Ex. From the given figure. According to question, This chapter deals with the basics of Geometry, parallel lines and transversal, pair of lines, angles and its types, Related angles and interior and exterior angles of triangles. (a) Let an angle be x. ∴ 2x + 1 = 2 × 44° + 1 = 88° + 1 = 890 Question 86: (d) (180 – b)° Question 5. ∴ ∠QRS – ∠TSR = 85° ———- (ii) [Using (i)] [Alternate interior angles] Complementary (ii) one arm is always common, and (i) b and c (ii) d and e (a) 1° (b) 11° Get Free NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.1 PDF. Also, AB || DF and BD is a transversal. If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles, drop a comment below and we will get back to you at the earliest. Since, a and b form a linear pair. True ∴ ∠1 = 34° [Alternate interior angles] ∴ (90 – x)°= 79° (i) Name all the pairs of adjacent angles. ⇒ 90° + x + y = 180° Jul 18, 2018 - NCERT Exemplar Class 7 Maths Book PDF Download Chapter 5 Lines and Angles Solutions Multiple Choice Questions (MCQs) Question 1: The angles between North and West and South and East are (a) complementary (b) supplementary (c) both are acute (d) both are obtuse Solution : From the above figure, it is clear that the […] (a) one of its angles is acute? (a) ∠1 = ∠5 Solution : (c) Since, angles are on a straight line. In the given figure, ∠AOC and ∠BOC form a pair of If one of them is one-third of the other, then find the angles. ∠1, ∠2 ; ∠2, ∠3; ∠3, ∠4; ∠4, ∠1. Vertically opposite angles are either both acute angles or both obtuse angles. (c) Since, sum of all the angles on a straight line is 180°. (d) Vertically opposite angles are always equal. True Obtuse Sum of interior angles on the same side of a transversal is 180°. Solution : Solution: (ii) There is no pair of vertically opposite angles. ⇒ ∠x = 180° – 120° = 60° Question 21. (d) ∠AOC and ∠BOC form a pair of supplementary angles. In the given figure, PO || SR and SP | RQ. Solution : Since, lines l and mare parallel and p is transversal. (c) (45°, 45°) and (60°, 30°) are the two pairs of angles formed by different positions of two players such that they are complement to each other. Solution : Then, sum of two right angles will be (90°+ 90°) = 180°. ⇒ ∠2 = ∠y = 120° [Vertically opposite angles] ⇒ 100° + a = 180° Most of the questions asked in the annual examination are completely from the Class 7 Maths NCERT Books Solutions. ∴ a = 20° [Alternate interior angles] (d) both p and q are false ∠1 +∠2 = 180° [Angles on a straight line PQ] This chapter has 4 exercises and 35 in total. False Two alternate interior angles are on the opposite side of the transversal. (d) 120° When the sum of the measures of two angles is 180°, the angles are called supplementary angles. Solution : Two supplementary angles are always obtuse angles. These NCERT Solutions for Class 7 Maths Lines and Angles in Hindi medium pdf download have innumerable benefits as these are created in simple and easy-to-understand language. ⇒ ∠RQU = 35° ——- (ii) Two supplementary angles are always obtuse angles. Solution : (b) Since, PQ || ST and SO is a transversal. 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